-4(-m+2)+2=-1/2(10-12m)-3

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Solution for -4(-m+2)+2=-1/2(10-12m)-3 equation: 



-4(-m+2)+2=-1/2(10-12m)-3

We move all terms to the left:

-4(-m+2)+2-(-1/2(10-12m)-3)=0



Domain of the equation: 2(10-12m)-3)!=0

m∈R



We add all the numbers together, and all the variables

-4(-1m+2)-(-1/2(-12m+10)-3)+2=0

We multiply parentheses

4m-(-1/2(-12m+10)-3)-8+2=0

We multiply all the terms by the denominator


4m*2(-12m+10)-8*2(-12m+10)-12m-1-3)-(-3)+2*2(+10)-3)=0

We add all the numbers together, and all the variables

4m*2(-12m+10)-8*2(-12m+10)-12m-1-3)-(-3)+2*210-3)=0

We add all the numbers together, and all the variables

-12m+4m*2(-12m+10)-8*2(-12m+10)=0

Wy multiply elements

8m^2(--16m(--12m=0

We use the square of the difference formula

8m^2(+16m(+12m=0

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