40-5(d+12)=d2

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Solution for 40-5(d+12)=d2 equation: 



40-5(d+12)=d2

We move all terms to the left:

40-5(d+12)-(d2)=0

We add all the numbers together, and all the variables

-1d^2-5(d+12)+40=0

We multiply parentheses

-1d^2-5d-60+40=0

We add all the numbers together, and all the variables

-1d^2-5d-20=0

a = -1; b = -5; c = -20;
Δ = b2-4ac
Δ = -52-4·(-1)·(-20)
Δ = -55
Delta is less than zero, so there is no solution for the equation

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