2(x+4)+3x=6+3(x-4)

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Solution for 2(x+4)+3x=6+3(x-4) equation:



2(x+4)+3x=6+3(x-4)
We move all terms to the left:
2(x+4)+3x-(6+3(x-4))=0
We add all the numbers together, and all the variables
3x+2(x+4)-(6+3(x-4))=0
We multiply parentheses
3x+2x-(6+3(x-4))+8=0
We calculate terms in parentheses: -(6+3(x-4)), so:
6+3(x-4)
determiningTheFunctionDomain 3(x-4)+6
We multiply parentheses
3x-12+6
We add all the numbers together, and all the variables
3x-6
Back to the equation:
-(3x-6)
We add all the numbers together, and all the variables
5x-(3x-6)+8=0
We get rid of parentheses
5x-3x+6+8=0
We add all the numbers together, and all the variables
2x+14=0
We move all terms containing x to the left, all other terms to the right
2x=-14
x=-14/2
x=-7

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