(3/5)g-(1/3)=-(10/3)

Solution for (3/5)g-(1/3)=-(10/3) equation:

(3/5)g-(1/3)=-(10/3)

We move all terms to the left:

(3/5)g-(1/3)-(-(10/3))=0


Domain of the equation: 5)g!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

(+3/5)g-(+1/3)-(-(+10/3))=0

We multiply parentheses

3g^2-(+1/3)-(-(+10/3))=0

We get rid of parentheses

3g^2-1/3-(-(+10/3))=0

We calculate fractions


3g^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$g=\frac{-b}{2a}=\frac{0}{6}=0$