2(u-1)Z+8=6(2u-4)

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Solution for 2(u-1)Z+8=6(2u-4) equation: 



2(u-1)+8=6(2u-4)

We move all terms to the left:

2(u-1)+8-(6(2u-4))=0

We multiply parentheses

2u-(6(2u-4))-2+8=0



We calculate terms in parentheses: -(6(2u-4)), so:

6(2u-4)

We multiply parentheses

12u-24

Back to the equation:

-(12u-24)



We add all the numbers together, and all the variables

2u-(12u-24)+6=0

We get rid of parentheses

2u-12u+24+6=0

We add all the numbers together, and all the variables

-10u+30=0

We move all terms containing u to the left, all other terms to the right

-10u=-30

u=-30/-10

u=+3

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