2(x+3)=3x-2-(7+4x)

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Solution for 2(x+3)=3x-2-(7+4x) equation: 



2(x+3)=3x-2-(7+4x)

We move all terms to the left:

2(x+3)-(3x-2-(7+4x))=0

We add all the numbers together, and all the variables

2(x+3)-(3x-2-(4x+7))=0

We multiply parentheses

2x-(3x-2-(4x+7))+6=0



We calculate terms in parentheses: -(3x-2-(4x+7)), so:

3x-2-(4x+7)

determiningTheFunctionDomain
3x-(4x+7)-2

We get rid of parentheses

3x-4x-7-2

We add all the numbers together, and all the variables

-1x-9

Back to the equation:

-(-1x-9)



We get rid of parentheses

2x+1x+9+6=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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