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2(x+20)=3(2x+4)
We move all terms to the left:
2(x+20)-(3(2x+4))=0
We multiply parentheses
2x-(3(2x+4))+40=0
We calculate terms in parentheses: -(3(2x+4)), so:We get rid of parentheses
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
2x-6x-12+40=0
We add all the numbers together, and all the variables
-4x+28=0
We move all terms containing x to the left, all other terms to the right
-4x=-28
x=-28/-4
x=+7
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