23=3(u-6)+2u

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Solution for 23=3(u-6)+2u equation: 



23=3(u-6)+2u

We move all terms to the left:

23-(3(u-6)+2u)=0



We calculate terms in parentheses: -(3(u-6)+2u), so:

3(u-6)+2u

We add all the numbers together, and all the variables

2u+3(u-6)

We multiply parentheses

2u+3u-18

We add all the numbers together, and all the variables

5u-18

Back to the equation:

-(5u-18)



We get rid of parentheses

-5u+18+23=0

We add all the numbers together, and all the variables

-5u+41=0

We move all terms containing u to the left, all other terms to the right

-5u=-41

u=-41/-5

u=8+1/5

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