5(1+f)=7(f-3)

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Solution for 5(1+f)=7(f-3) equation:



5(1+f)=7(f-3)
We move all terms to the left:
5(1+f)-(7(f-3))=0
We add all the numbers together, and all the variables
5(f+1)-(7(f-3))=0
We multiply parentheses
5f-(7(f-3))+5=0
We calculate terms in parentheses: -(7(f-3)), so:
7(f-3)
We multiply parentheses
7f-21
Back to the equation:
-(7f-21)
We get rid of parentheses
5f-7f+21+5=0
We add all the numbers together, and all the variables
-2f+26=0
We move all terms containing f to the left, all other terms to the right
-2f=-26
f=-26/-2
f=+13

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