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2(x+2)-5=3(x+1)
We move all terms to the left:
2(x+2)-5-(3(x+1))=0
We multiply parentheses
2x-(3(x+1))+4-5=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
2x-(3x+3)-1=0
We get rid of parentheses
2x-3x-3-1=0
We add all the numbers together, and all the variables
-1x-4=0
We move all terms containing x to the left, all other terms to the right
-x=4
x=4/-1
x=-4
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