3(m+3)-5=2(m+8)

Solution for 3(m+3)-5=2(m+8) equation:

3(m+3)-5=2(m+8)

We move all terms to the left:

3(m+3)-5-(2(m+8))=0

We multiply parentheses

3m-(2(m+8))+9-5=0


We calculate terms in parentheses: -(2(m+8)), so:

2(m+8)

We multiply parentheses

2m+16

Back to the equation:

-(2m+16)


We add all the numbers together, and all the variables

3m-(2m+16)+4=0

We get rid of parentheses

3m-2m-16+4=0

We add all the numbers together, and all the variables

m-12=0

We move all terms containing m to the left, all other terms to the right

m=12