2(y+1)+2(4y+5)=62

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Solution for 2(y+1)+2(4y+5)=62 equation: 



2(y+1)+2(4y+5)=62

We move all terms to the left:

2(y+1)+2(4y+5)-(62)=0

We multiply parentheses

2y+8y+2+10-62=0

We add all the numbers together, and all the variables

10y-50=0

We move all terms containing y to the left, all other terms to the right

10y=50

y=50/10

y=5

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