3(2y+1)=2(y+3)-4

Solution for 3(2y+1)=2(y+3)-4 equation:

3(2y+1)=2(y+3)-4

We move all terms to the left:

3(2y+1)-(2(y+3)-4)=0

We multiply parentheses

6y-(2(y+3)-4)+3=0


We calculate terms in parentheses: -(2(y+3)-4), so:

2(y+3)-4

We multiply parentheses

2y+6-4

We add all the numbers together, and all the variables

2y+2

Back to the equation:

-(2y+2)


We get rid of parentheses

6y-2y-2+3=0

We add all the numbers together, and all the variables

4y+1=0

We move all terms containing y to the left, all other terms to the right

4y=-1

y=-1/4

y=-1/4