2(x+2)+6x=4(3x-2)

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Solution for 2(x+2)+6x=4(3x-2) equation: 



2(x+2)+6x=4(3x-2)

We move all terms to the left:

2(x+2)+6x-(4(3x-2))=0

We add all the numbers together, and all the variables

6x+2(x+2)-(4(3x-2))=0

We multiply parentheses

6x+2x-(4(3x-2))+4=0



We calculate terms in parentheses: -(4(3x-2)), so:

4(3x-2)

We multiply parentheses

12x-8

Back to the equation:

-(12x-8)



We add all the numbers together, and all the variables

8x-(12x-8)+4=0

We get rid of parentheses

8x-12x+8+4=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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