5(r+3)-6=3(r-2)-2r

Solution for 5(r+3)-6=3(r-2)-2r equation:

5(r+3)-6=3(r-2)-2r

We move all terms to the left:

5(r+3)-6-(3(r-2)-2r)=0

We multiply parentheses

5r-(3(r-2)-2r)+15-6=0


We calculate terms in parentheses: -(3(r-2)-2r), so:

3(r-2)-2r

We add all the numbers together, and all the variables

-2r+3(r-2)

We multiply parentheses

-2r+3r-6

We add all the numbers together, and all the variables

r-6

Back to the equation:

-(r-6)


We add all the numbers together, and all the variables

5r-(r-6)+9=0

We get rid of parentheses

5r-r+6+9=0

We add all the numbers together, and all the variables

4r+15=0

We move all terms containing r to the left, all other terms to the right

4r=-15

r=-15/4

r=-3+3/4