3+2(b+1)=3b+6

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Solution for 3+2(b+1)=3b+6 equation: 



3+2(b+1)=3b+6

We move all terms to the left:

3+2(b+1)-(3b+6)=0

We multiply parentheses

2b-(3b+6)+2+3=0

We get rid of parentheses

2b-3b-6+2+3=0

We add all the numbers together, and all the variables

-1b-1=0

We move all terms containing b to the left, all other terms to the right

-b=1

b=1/-1

b=-1

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