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2(x+1)=4(3-x)-10
We move all terms to the left:
2(x+1)-(4(3-x)-10)=0
We add all the numbers together, and all the variables
2(x+1)-(4(-1x+3)-10)=0
We multiply parentheses
2x-(4(-1x+3)-10)+2=0
We calculate terms in parentheses: -(4(-1x+3)-10), so:We get rid of parentheses
4(-1x+3)-10
We multiply parentheses
-4x+12-10
We add all the numbers together, and all the variables
-4x+2
Back to the equation:
-(-4x+2)
2x+4x-2+2=0
We add all the numbers together, and all the variables
6x=0
x=0/6
x=0
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