2(1+4k)+7(k-4)=64

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Solution for 2(1+4k)+7(k-4)=64 equation:



2(1+4k)+7(k-4)=64
We move all terms to the left:
2(1+4k)+7(k-4)-(64)=0
We add all the numbers together, and all the variables
2(4k+1)+7(k-4)-64=0
We multiply parentheses
8k+7k+2-28-64=0
We add all the numbers together, and all the variables
15k-90=0
We move all terms containing k to the left, all other terms to the right
15k=90
k=90/15
k=6

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