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3(x-3)=2x+12
We move all terms to the left:
3(x-3)-(2x+12)=0
We multiply parentheses
3x-(2x+12)-9=0
We get rid of parentheses
3x-2x-12-9=0
We add all the numbers together, and all the variables
x-21=0
We move all terms containing x to the left, all other terms to the right
x=21
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