2(x+1)=10(1-3x)

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Solution for 2(x+1)=10(1-3x) equation: 



2(x+1)=10(1-3x)

We move all terms to the left:

2(x+1)-(10(1-3x))=0

We add all the numbers together, and all the variables

2(x+1)-(10(-3x+1))=0

We multiply parentheses

2x-(10(-3x+1))+2=0



We calculate terms in parentheses: -(10(-3x+1)), so:

10(-3x+1)

We multiply parentheses

-30x+10

Back to the equation:

-(-30x+10)



We get rid of parentheses

2x+30x-10+2=0

We add all the numbers together, and all the variables

32x-8=0

We move all terms containing x to the left, all other terms to the right

32x=8

x=8/32

x=1/4

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