2(x+1)/5=2(x+7)/13

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Solution for 2(x+1)/5=2(x+7)/13 equation: 



2(x+1)/5=2(x+7)/13

We move all terms to the left:

2(x+1)/5-(2(x+7)/13)=0

We calculate fractions


2x/()+(-(2(x+7)*5)/()=0



We calculate terms in parentheses: +(-(2(x+7)*5)/(), so:

-(2(x+7)*5)/(

We multiply all the terms by the denominator


-(2(x+7)*5)



We calculate terms in parentheses: -(2(x+7)*5), so:

2(x+7)*5

We multiply parentheses

10x+70

Back to the equation:

-(10x+70)



We get rid of parentheses

-10x-70

Back to the equation:

+(-10x-70)



We get rid of parentheses

2x/()-10x-70=0

We multiply all the terms by the denominator


2x-10x*()-70*()=0

We add all the numbers together, and all the variables

2x-10x*()=0

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