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4(x-15)=3(x+5)
We move all terms to the left:
4(x-15)-(3(x+5))=0
We multiply parentheses
4x-(3(x+5))-60=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
4x-3x-15-60=0
We add all the numbers together, and all the variables
x-75=0
We move all terms containing x to the left, all other terms to the right
x=75
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