2(w-1)+4=2(w+1)-2(-w-1)

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Solution for 2(w-1)+4=2(w+1)-2(-w-1) equation: 



2(w-1)+4=2(w+1)-2(-w-1)

We move all terms to the left:

2(w-1)+4-(2(w+1)-2(-w-1))=0

We add all the numbers together, and all the variables

2(w-1)-(2(w+1)-2(-1w-1))+4=0

We multiply parentheses

2w-(2(w+1)-2(-1w-1))-2+4=0



We calculate terms in parentheses: -(2(w+1)-2(-1w-1)), so:

2(w+1)-2(-1w-1)

We multiply parentheses

2w+2w+2+2

We add all the numbers together, and all the variables

4w+4

Back to the equation:

-(4w+4)



We add all the numbers together, and all the variables

2w-(4w+4)+2=0

We get rid of parentheses

2w-4w-4+2=0

We add all the numbers together, and all the variables

-2w-2=0

We move all terms containing w to the left, all other terms to the right

-2w=2

w=2/-2

w=-1

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