6k-(5k+5)=-8-2(k+12)

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Solution for 6k-(5k+5)=-8-2(k+12) equation: 



6k-(5k+5)=-8-2(k+12)

We move all terms to the left:

6k-(5k+5)-(-8-2(k+12))=0

We get rid of parentheses

6k-5k-(-8-2(k+12))-5=0



We calculate terms in parentheses: -(-8-2(k+12)), so:

-8-2(k+12)

determiningTheFunctionDomain
-2(k+12)-8

We multiply parentheses

-2k-24-8

We add all the numbers together, and all the variables

-2k-32

Back to the equation:

-(-2k-32)



We add all the numbers together, and all the variables

k-(-2k-32)-5=0

We get rid of parentheses

k+2k+32-5=0

We add all the numbers together, and all the variables

3k+27=0

We move all terms containing k to the left, all other terms to the right

3k=-27

k=-27/3

k=-9

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