2(u-1)+4u=3(u+1)

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Solution for 2(u-1)+4u=3(u+1) equation: 



2(u-1)+4u=3(u+1)

We move all terms to the left:

2(u-1)+4u-(3(u+1))=0

We add all the numbers together, and all the variables

4u+2(u-1)-(3(u+1))=0

We multiply parentheses

4u+2u-(3(u+1))-2=0



We calculate terms in parentheses: -(3(u+1)), so:

3(u+1)

We multiply parentheses

3u+3

Back to the equation:

-(3u+3)



We add all the numbers together, and all the variables

6u-(3u+3)-2=0

We get rid of parentheses

6u-3u-3-2=0

We add all the numbers together, and all the variables

3u-5=0

We move all terms containing u to the left, all other terms to the right

3u=5

u=5/3

u=1+2/3

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