2(t-5)=4t-7(t+3)

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Solution for 2(t-5)=4t-7(t+3) equation: 



2(t-5)=4t-7(t+3)

We move all terms to the left:

2(t-5)-(4t-7(t+3))=0

We multiply parentheses

2t-(4t-7(t+3))-10=0



We calculate terms in parentheses: -(4t-7(t+3)), so:

4t-7(t+3)

We multiply parentheses

4t-7t-21

We add all the numbers together, and all the variables

-3t-21

Back to the equation:

-(-3t-21)



We get rid of parentheses

2t+3t+21-10=0

We add all the numbers together, and all the variables

5t+11=0

We move all terms containing t to the left, all other terms to the right

5t=-11

t=-11/5

t=-2+1/5

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