(6x2-9x-24)=2/3

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Solution for (6x2-9x-24)=2/3 equation:



(6x^2-9x-24)=2/3
We move all terms to the left:
(6x^2-9x-24)-(2/3)=0
We add all the numbers together, and all the variables
(6x^2-9x-24)-(+2/3)=0
We get rid of parentheses
6x^2-9x-24-2/3=0
We multiply all the terms by the denominator
6x^2*3-9x*3-2-24*3=0
We add all the numbers together, and all the variables
6x^2*3-9x*3-74=0
Wy multiply elements
18x^2-27x-74=0
a = 18; b = -27; c = -74;
Δ = b2-4ac
Δ = -272-4·18·(-74)
Δ = 6057
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6057}=\sqrt{9*673}=\sqrt{9}*\sqrt{673}=3\sqrt{673}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3\sqrt{673}}{2*18}=\frac{27-3\sqrt{673}}{36} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3\sqrt{673}}{2*18}=\frac{27+3\sqrt{673}}{36} $

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