12y-18=6(2y-3)

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Solution for 12y-18=6(2y-3) equation: 



12y-18=6(2y-3)

We move all terms to the left:

12y-18-(6(2y-3))=0



We calculate terms in parentheses: -(6(2y-3)), so:

6(2y-3)

We multiply parentheses

12y-18

Back to the equation:

-(12y-18)



We get rid of parentheses

12y-12y+18-18=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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