2(t-1)-3(2t-1)=3-5(4t+1)

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Solution for 2(t-1)-3(2t-1)=3-5(4t+1) equation: 



2(t-1)-3(2t-1)=3-5(4t+1)

We move all terms to the left:

2(t-1)-3(2t-1)-(3-5(4t+1))=0

We multiply parentheses

2t-6t-(3-5(4t+1))-2+3=0



We calculate terms in parentheses: -(3-5(4t+1)), so:

3-5(4t+1)

determiningTheFunctionDomain
-5(4t+1)+3

We multiply parentheses

-20t-5+3

We add all the numbers together, and all the variables

-20t-2

Back to the equation:

-(-20t-2)



We add all the numbers together, and all the variables

-4t-(-20t-2)+1=0

We get rid of parentheses

-4t+20t+2+1=0

We add all the numbers together, and all the variables

16t+3=0

We move all terms containing t to the left, all other terms to the right

16t=-3

t=-3/16

t=-3/16

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