(7h-8)/4=(5-h)/2

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Solution for (7h-8)/4=(5-h)/2 equation: 



(7h-8)/4=(5-h)/2

We move all terms to the left:

(7h-8)/4-((5-h)/2)=0

We add all the numbers together, and all the variables

(7h-8)/4-((-1h+5)/2)=0

We calculate fractions


7h/()+(-((-1h+5)*4)/()=0



We calculate terms in parentheses: +(-((-1h+5)*4)/(), so:

-((-1h+5)*4)/(

We multiply all the terms by the denominator


-((-1h+5)*4)



We calculate terms in parentheses: -((-1h+5)*4), so:

(-1h+5)*4

We multiply parentheses

-4h+20

Back to the equation:

-(-4h+20)



We get rid of parentheses

4h-20

Back to the equation:

+(4h-20)



We get rid of parentheses

7h/()+4h-20=0

We multiply all the terms by the denominator


7h+4h*()-20*()=0

We add all the numbers together, and all the variables

7h+4h*()=0

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