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(2x+3)(2x)=560
We move all terms to the left:
(2x+3)(2x)-(560)=0
We multiply parentheses
4x^2+6x-560=0
a = 4; b = 6; c = -560;
Δ = b2-4ac
Δ = 62-4·4·(-560)
Δ = 8996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8996}=\sqrt{4*2249}=\sqrt{4}*\sqrt{2249}=2\sqrt{2249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{2249}}{2*4}=\frac{-6-2\sqrt{2249}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{2249}}{2*4}=\frac{-6+2\sqrt{2249}}{8} $
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