2(t-1)-3(4t-7)=22-6(5t+4)

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Solution for 2(t-1)-3(4t-7)=22-6(5t+4) equation: 



2(t-1)-3(4t-7)=22-6(5t+4)

We move all terms to the left:

2(t-1)-3(4t-7)-(22-6(5t+4))=0

We multiply parentheses

2t-12t-(22-6(5t+4))-2+21=0



We calculate terms in parentheses: -(22-6(5t+4)), so:

22-6(5t+4)

determiningTheFunctionDomain
-6(5t+4)+22

We multiply parentheses

-30t-24+22

We add all the numbers together, and all the variables

-30t-2

Back to the equation:

-(-30t-2)



We add all the numbers together, and all the variables

-10t-(-30t-2)+19=0

We get rid of parentheses

-10t+30t+2+19=0

We add all the numbers together, and all the variables

20t+21=0

We move all terms containing t to the left, all other terms to the right

20t=-21

t=-21/20

t=-1+1/20

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