2(n-3)+6(n+1)=n+2

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Solution for 2(n-3)+6(n+1)=n+2 equation: 



2(n-3)+6(n+1)=n+2

We move all terms to the left:

2(n-3)+6(n+1)-(n+2)=0

We multiply parentheses

2n+6n-(n+2)-6+6=0

We get rid of parentheses

2n+6n-n-2-6+6=0

We add all the numbers together, and all the variables

7n-2=0

We move all terms containing n to the left, all other terms to the right

7n=2

n=2/7

n=2/7

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