2(n+4)+3(n-4)=11

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Solution for 2(n+4)+3(n-4)=11 equation: 



2(n+4)+3(n-4)=11

We move all terms to the left:

2(n+4)+3(n-4)-(11)=0

We multiply parentheses

2n+3n+8-12-11=0

We add all the numbers together, and all the variables

5n-15=0

We move all terms containing n to the left, all other terms to the right

5n=15

n=15/5

n=3

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