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(9x^2)+(25x)-(6)=0
a = 9; b = 25; c = -6;
Δ = b2-4ac
Δ = 252-4·9·(-6)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-29}{2*9}=\frac{-54}{18} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+29}{2*9}=\frac{4}{18} =2/9 $
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