19=-(2b+3)-5(3b-1)

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Solution for 19=-(2b+3)-5(3b-1) equation: 



19=-(2b+3)-5(3b-1)

We move all terms to the left:

19-(-(2b+3)-5(3b-1))=0



We calculate terms in parentheses: -(-(2b+3)-5(3b-1)), so:

-(2b+3)-5(3b-1)

We multiply parentheses

-(2b+3)-15b+5

We get rid of parentheses

-2b-15b-3+5

We add all the numbers together, and all the variables

-17b+2

Back to the equation:

-(-17b+2)



We get rid of parentheses

17b-2+19=0

We add all the numbers together, and all the variables

17b+17=0

We move all terms containing b to the left, all other terms to the right

17b=-17

b=-17/17

b=-1

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