2(n+3)=-65-5(n-3)

Solution for 2(n+3)=-65-5(n-3) equation:

2(n+3)=-65-5(n-3)

We move all terms to the left:

2(n+3)-(-65-5(n-3))=0

We multiply parentheses

2n-(-65-5(n-3))+6=0


We calculate terms in parentheses: -(-65-5(n-3)), so:

-65-5(n-3)

determiningTheFunctionDomain
-5(n-3)-65

We multiply parentheses

-5n+15-65

We add all the numbers together, and all the variables

-5n-50

Back to the equation:

-(-5n-50)


We get rid of parentheses

2n+5n+50+6=0

We add all the numbers together, and all the variables

7n+56=0

We move all terms containing n to the left, all other terms to the right

7n=-56

n=-56/7

n=-8