(x+7)+(3x+20)=(6x-5)

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Solution for (x+7)+(3x+20)=(6x-5) equation: 



(x+7)+(3x+20)=(6x-5)

We move all terms to the left:

(x+7)+(3x+20)-((6x-5))=0

We get rid of parentheses

x+3x-((6x-5))+7+20=0



We calculate terms in parentheses: -((6x-5)), so:

(6x-5)

We get rid of parentheses

6x-5

Back to the equation:

-(6x-5)



We add all the numbers together, and all the variables

4x-(6x-5)+27=0

We get rid of parentheses

4x-6x+5+27=0

We add all the numbers together, and all the variables

-2x+32=0

We move all terms containing x to the left, all other terms to the right

-2x=-32

x=-32/-2

x=+16

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