16x2+14x-15=0

Solution for 16x2+14x-15=0 equation:

16x^2+14x-15=0

a = 16; b = 14; c = -15;
Δ = b2-4ac
Δ = 142-4·16·(-15)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-34}{2*16}=\frac{-48}{32}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+34}{2*16}=\frac{20}{32}
=5/8
$