2(k-3)=4(k-6)

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Solution for 2(k-3)=4(k-6) equation: 



2(k-3)=4(k-6)

We move all terms to the left:

2(k-3)-(4(k-6))=0

We multiply parentheses

2k-(4(k-6))-6=0



We calculate terms in parentheses: -(4(k-6)), so:

4(k-6)

We multiply parentheses

4k-24

Back to the equation:

-(4k-24)



We get rid of parentheses

2k-4k+24-6=0

We add all the numbers together, and all the variables

-2k+18=0

We move all terms containing k to the left, all other terms to the right

-2k=-18

k=-18/-2

k=+9

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