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3x(7x-1)=41
We move all terms to the left:
3x(7x-1)-(41)=0
We multiply parentheses
21x^2-3x-41=0
a = 21; b = -3; c = -41;
Δ = b2-4ac
Δ = -32-4·21·(-41)
Δ = 3453
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{3453}}{2*21}=\frac{3-\sqrt{3453}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{3453}}{2*21}=\frac{3+\sqrt{3453}}{42} $
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