(4x+4)x(4x+4)=21(3x+24)

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Solution for (4x+4)x(4x+4)=21(3x+24) equation: 



(4x+4)x(4x+4)=21(3x+24)

We move all terms to the left:

(4x+4)x(4x+4)-(21(3x+24))=0



We calculate terms in parentheses: -(21(3x+24)), so:

21(3x+24)

We multiply parentheses

63x+504

Back to the equation:

-(63x+504)



We get rid of parentheses

(4x+4)x(4x+4)-63x-504=0

We add all the numbers together, and all the variables

-63x+(4x+4)x(4x+4)-504=0

We move all terms containing x to the left, all other terms to the right

-63x+(4x+4)x(4x+4)=504

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