2(h-7)h=h-14

Solution for 2(h-7)h=h-14 equation:

2(h-7)h=h-14

We move all terms to the left:

2(h-7)h-(h-14)=0

We multiply parentheses

2h^2-14h-(h-14)=0

We get rid of parentheses

2h^2-14h-h+14=0

We add all the numbers together, and all the variables

2h^2-15h+14=0

a = 2; b = -15; c = +14;
Δ = b2-4ac
Δ = -152-4·2·14
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{113}}{2*2}=\frac{15-\sqrt{113}}{4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{113}}{2*2}=\frac{15+\sqrt{113}}{4}
$