2(b-2)-6=4(b+4)

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Solution for 2(b-2)-6=4(b+4) equation: 



2(b-2)-6=4(b+4)

We move all terms to the left:

2(b-2)-6-(4(b+4))=0

We multiply parentheses

2b-(4(b+4))-4-6=0



We calculate terms in parentheses: -(4(b+4)), so:

4(b+4)

We multiply parentheses

4b+16

Back to the equation:

-(4b+16)



We add all the numbers together, and all the variables

2b-(4b+16)-10=0

We get rid of parentheses

2b-4b-16-10=0

We add all the numbers together, and all the variables

-2b-26=0

We move all terms containing b to the left, all other terms to the right

-2b=26

b=26/-2

b=-13

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