6-(x-3)=2(x+8)

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Solution for 6-(x-3)=2(x+8) equation: 



6-(x-3)=2(x+8)

We move all terms to the left:

6-(x-3)-(2(x+8))=0

We get rid of parentheses

-x-(2(x+8))+3+6=0



We calculate terms in parentheses: -(2(x+8)), so:

2(x+8)

We multiply parentheses

2x+16

Back to the equation:

-(2x+16)



We add all the numbers together, and all the variables

-1x-(2x+16)+9=0

We get rid of parentheses

-1x-2x-16+9=0

We add all the numbers together, and all the variables

-3x-7=0

We move all terms containing x to the left, all other terms to the right

-3x=7

x=7/-3

x=-2+1/3

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