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2(a-4)=4a-(2a/4)
We move all terms to the left:
2(a-4)-(4a-(2a/4))=0
We add all the numbers together, and all the variables
2(a-4)-(4a-(+2a/4))=0
We multiply parentheses
2a-(4a-(+2a/4))-8=0
We multiply all the terms by the denominator
2a*4))-(4a-(+2a-8*4))=0
We add all the numbers together, and all the variables
2a*4))-(4a-(2a-32))=0
We add all the numbers together, and all the variables
2a*4))-(4a-(2a=0
Wy multiply elements
8a^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{16}=0$
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