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2(6x-4)+4(3x-2)=9(1x-8)+7(x-4)
We move all terms to the left:
2(6x-4)+4(3x-2)-(9(1x-8)+7(x-4))=0
We add all the numbers together, and all the variables
2(6x-4)+4(3x-2)-(9(x-8)+7(x-4))=0
We multiply parentheses
12x+12x-(9(x-8)+7(x-4))-8-8=0
We calculate terms in parentheses: -(9(x-8)+7(x-4)), so:We add all the numbers together, and all the variables
9(x-8)+7(x-4)
We multiply parentheses
9x+7x-72-28
We add all the numbers together, and all the variables
16x-100
Back to the equation:
-(16x-100)
24x-(16x-100)-16=0
We get rid of parentheses
24x-16x+100-16=0
We add all the numbers together, and all the variables
8x+84=0
We move all terms containing x to the left, all other terms to the right
8x=-84
x=-84/8
x=-10+1/2
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