6(3x+1)-30=3(x-4)

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Solution for 6(3x+1)-30=3(x-4) equation: 



6(3x+1)-30=3(x-4)

We move all terms to the left:

6(3x+1)-30-(3(x-4))=0

We multiply parentheses

18x-(3(x-4))+6-30=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

18x-(3x-12)-24=0

We get rid of parentheses

18x-3x+12-24=0

We add all the numbers together, and all the variables

15x-12=0

We move all terms containing x to the left, all other terms to the right

15x=12

x=12/15

x=4/5

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