2(6-2x)=20+2(x-1)

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Solution for 2(6-2x)=20+2(x-1) equation: 



2(6-2x)=20+2(x-1)

We move all terms to the left:

2(6-2x)-(20+2(x-1))=0

We add all the numbers together, and all the variables

2(-2x+6)-(20+2(x-1))=0

We multiply parentheses

-4x-(20+2(x-1))+12=0



We calculate terms in parentheses: -(20+2(x-1)), so:

20+2(x-1)

determiningTheFunctionDomain
2(x-1)+20

We multiply parentheses

2x-2+20

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We get rid of parentheses

-4x-2x-18+12=0

We add all the numbers together, and all the variables

-6x-6=0

We move all terms containing x to the left, all other terms to the right

-6x=6

x=6/-6

x=-1

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