(10x-1)=(3x+17)+(2x+12)

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Solution for (10x-1)=(3x+17)+(2x+12) equation: 



(10x-1)=(3x+17)+(2x+12)

We move all terms to the left:

(10x-1)-((3x+17)+(2x+12))=0

We get rid of parentheses

10x-((3x+17)+(2x+12))-1=0



We calculate terms in parentheses: -((3x+17)+(2x+12)), so:

(3x+17)+(2x+12)

We get rid of parentheses

3x+2x+17+12

We add all the numbers together, and all the variables

5x+29

Back to the equation:

-(5x+29)



We get rid of parentheses

10x-5x-29-1=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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